Procedure:
(i) excavate a pit of required depth.
(ii) take a iron cube or ball (whose dimension and weight are known)
(iii) drop the cube or ball several times, from known height on the excavate pit.
(iv) calculate the average value of the depth.
R = (w×h)/d
Where
R - ultimate resistance of soil in kg.
d - average depth of impression in (cm).
w - weight of solid ball or square cube in kg.
h - height of fall ball of cube.
Example:
Cube weight = 5 kg
Height of fall = 150 mm
Depth of impression - 9 cm,8.5 cm,6 cm,5 cm and 4 cm
Solution:-
Average depth of impression
d = (9+8.5+6+5+4)/5 cm
= 6.5 cm
R = (w×h)/d
= (5×150)/6.5
= 115.38 kg
Then, resistance of soil per unite area
= R/A kg/cm×cm
= 115.38/(15×15) kg/cm×cm
= 0.51 kg/cm×cm
Safe bearing capacity of soil = R/(A×fos)
fos - resistance of soil per unite area reduce 2 to 3 times
Safe bearing capacity of soil = 115.38/(15×15×2) kg/ cm×cm
= 0.256 kg/ cm×cm ans.
For more information about this topic watch video link below.
https://youtu.be/sRspDdTRbVI
Facebook link.
https://www.facebook.com/sehbud.alam.52
Twitter link.
https://twitter.com/Sehbudalam7?s=09
Telegram link.
https://t.me/officialtkalam
Thnk you for visit.
(i) excavate a pit of required depth.
(ii) take a iron cube or ball (whose dimension and weight are known)
(iii) drop the cube or ball several times, from known height on the excavate pit.
(iv) calculate the average value of the depth.
R = (w×h)/d
Where
R - ultimate resistance of soil in kg.
d - average depth of impression in (cm).
w - weight of solid ball or square cube in kg.
h - height of fall ball of cube.
Example:
Cube weight = 5 kg
Height of fall = 150 mm
Depth of impression - 9 cm,8.5 cm,6 cm,5 cm and 4 cm
Solution:-
Average depth of impression
d = (9+8.5+6+5+4)/5 cm
= 6.5 cm
R = (w×h)/d
= (5×150)/6.5
= 115.38 kg
Then, resistance of soil per unite area
= R/A kg/cm×cm
= 115.38/(15×15) kg/cm×cm
= 0.51 kg/cm×cm
Safe bearing capacity of soil = R/(A×fos)
fos - resistance of soil per unite area reduce 2 to 3 times
Safe bearing capacity of soil = 115.38/(15×15×2) kg/ cm×cm
= 0.256 kg/ cm×cm ans.
For more information about this topic watch video link below.
https://youtu.be/sRspDdTRbVI
Facebook link.
https://www.facebook.com/sehbud.alam.52
Twitter link.
https://twitter.com/Sehbudalam7?s=09
Telegram link.
https://t.me/officialtkalam
Thnk you for visit.
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