According to IS-456 2000 find out the size of column need.
. Load
. Grade of concrete
. Characteristic strength of the compression reinforcement
Formula:
Pu = (0.4fck×Ac)+(0.67×Fy×Asc)
Where Pu = ultimate load
Fck = characteristic compressive strength of the concrete
Ac = Area of concrete
Fy = characteristic strength of the compression reinforcement
. Load
. Grade of concrete
. Characteristic strength of the compression reinforcement
Formula:
Pu = (0.4fck×Ac)+(0.67×Fy×Asc)
Where Pu = ultimate load
Fck = characteristic compressive strength of the concrete
Ac = Area of concrete
Fy = characteristic strength of the compression reinforcement
Asc = area of longitudinal reinforcement for concrete
Example: imposed load 2000 kn act on the column size M20 grade Fe 415 grade steel. Find out the size of column.
Solution:
Given
Pu = 2000 kn
Fck = 20 N/mm square
Fy = 415 N/mm square
Safety factor = 10% of load
= (10/100)×2000 kn
= 200 kn
Total load = 2000+200
= 2200 kn
Grosss area= 100%
Asc = 1% Ag
Ac = 99% Ag
Pu = (0.4×fck×Ac)+(0.67×fy×Asc)
2200×1000 = (0.4×20×0.99Ag)+ (0.67×415×0.01Ag)
2200×1000 = 7.92Ag+2.7805Ag
22000×1000 = 10.7005Ag
Ag = (2200×1000)/10.7005
Ag = 205597.869 mm square
Square size of column
a×a = 205597.869 mm square
a = 453.42 mm ans.
Asc = 1% Ag
Ac = 99% Ag
Pu = (0.4×fck×Ac)+(0.67×fy×Asc)
2200×1000 = (0.4×20×0.99Ag)+ (0.67×415×0.01Ag)
2200×1000 = 7.92Ag+2.7805Ag
22000×1000 = 10.7005Ag
Ag = (2200×1000)/10.7005
Ag = 205597.869 mm square
Square size of column
a×a = 205597.869 mm square
a = 453.42 mm ans.
More information about size of column watch video link below.
https://youtu.be/kQdKN8-vA_c
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